print1418. Restaurant tab

printRestaurant tab

Ограничения: время – 5s/10s, память – 64MiB Ввод: input.txt или стандартный ввод Вывод: output.txt или стандартный вывод copy
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After eating dinner at a restaurant with some friends, you determine how much money each person owes. Each of you has some cash and some change, but very few of you have exact change. Can you make change for each other so that each person ends up paying the exact right amount?
The input file will contain multiple cases. The first line of each case is `N`, the number of people at the table. This is followed by `N` lines, one for each `i\ ∈\ [1,N]`, containing
`x_i\ c_{i,1}\ c_{i,5}\ c_{i,10}\ c_{i,25}\ c_{i,100}\ c_{i,500}\ c_{i,1000}\ c_{i,2000}\ c_{i,5000}\ c_{i,10000}`
where `x_i` is the amount in cents that person `i` owes and `c_i,v` is the number of coins or bills worth `v` cents that person `i` starts out with. For example, person 1 has `c_{1,1}` pennies, `c_{1,5}` nickels, etc.
Each case is followed immediately by the next case. The end of the input is indicated by a line containing only a zero.
You may assume that no person owes more money than they have (i.e. `x_i\ ≤\ ∑_j\ j*c_j`) and that the total amount of money in cents that everyone starts with fits in a signed 32-bit integer. You may also assume that `N\ ≤\ 100000`.
For each case, output the case number, in the format "Case #:" (where # is the case number, starting at 1), followed by a space, followed by "YES" if all of the money can be rearranged so that each person ends up paying the correct amount and "NO" if not.

Sample Input

10 0 0 1 0 0 0 0 0 0 0
0 0 0 0 0 2 0 0 0 0 0
500 0 0 0 0 0 1 0 0 0 0
100 4 0 2 3 0 1 0 0 0 0

Sample Output

Case 1: YES
Case 2: YES
Case 3: NO
Source: MIT Programming Contest, Individual Round, 2008